6x^2+28x-2=2x+10

Solution for 6x^2+28x-2=2x+10 equation:

6x^2+28x-2=2x+10

We move all terms to the left:

6x^2+28x-2-(2x+10)=0

We get rid of parentheses

6x^2+28x-2x-10-2=0

We add all the numbers together, and all the variables

6x^2+26x-12=0

a = 6; b = 26; c = -12;
Δ = b2-4ac
Δ = 262-4·6·(-12)
Δ = 964
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{964}=\sqrt{4*241}=\sqrt{4}*\sqrt{241}=2\sqrt{241}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-2\sqrt{241}}{2*6}=\frac{-26-2\sqrt{241}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+2\sqrt{241}}{2*6}=\frac{-26+2\sqrt{241}}{12}
$